(i) Which of the bodies is moving with Question 5. Calculate: Question 1. What is essential to describe the position of an object? Answer: Answer: The table given below shows distance (in cm) travelled by bodies A, B and C. Read this data carefully and answer the following questions. (b) minimum distance in 3rd second? If the velocity of a body decreases with time, then its final velocity is less than the initial velocity and thus its acceleration is negative. Calculate the speed of the body as it moves from So, On the other hand, the object Q covers 7 m from 9:30 am to 9:45 am, 4 m from 9:45 am to 10:00 am, and so on. A body is moving with a velocity of 10 m/s. So, the equations of motion will become Answer: A body travels along a circular path of radius 70 m. After travelling half a revolution in 20 s, find the This chapter is about the bonding of the atoms and types of bonding. Observe the graph carefully and answer the following questions. [NCERT Exemplar] This is why we present the book compilations in this website. or, 0 = 0.5 + (- 0.05t) ⇒ 0.5 = 0.05t, Answer: What is the relation between linear velocity and angular velocity? And by having access to our ebooks online or by storing it on your computer, you have convenient answers with Physics Short Questions Answers Class 9 . Velocity from 0 to 50 s is v1 = \(\frac{\Delta s}{\Delta t}=\frac{100-0}{50-0}\) = 2 ms-1 The velocity-time graph shows the motion of a cyclist. Answer: Finally I get this ebook, thanks for all these Physics Short Questions Answers Class 9 I can get now! An object starting from rest travels 20 m in first 2s and 160 m in next 4s. The velocity of the body increases by 2 m/s after every second. so many fake sites. [NCERT Exemplar] [lock] Acceleration = Slope of line OA = AD/OD How can we describe the location of an object? We have made it easy for you to find a PDF Ebooks without any digging. During upward motion, acceleration = -g and during downward motion acceleration = + g. Times of upward and downward motion is equal. (ii) v2 = u2 + 2as Question 5. Students must understand the concepts of the subject properly in order to score well in their exams. Answer: Question 12. From equations (1) and (2), Slope of line PQ = tanθ = \(\frac{Q R}{P R}\) PDF download of these motion class 9 numericals is also available. = Area of ∆ORS Question 21. Speed = \(\frac{\text { Distance }}{\text { Time }}=\frac{0}{(7-5) \mathrm{s}}=\frac{0}{2 \mathrm{s}}\) = 0 Thus, Answer: Answer: s2 = 40 × 4 = 160 m Question 2. = Area of rectangle DABE = DA × DE Average velocity = 90 km/h = \(\frac{90 \mathrm{km}}{1 \mathrm{h}}\) No. = Shortest distance between initial and final positions lol it did not even take me 5 minutes at all! Which car is the slowest? Final velocity, v= 0 (ii) What is the average speed of the train? What indicates the motion of the earth? In other words, it is under retardation. Answer: What do you mean by average speed? Also find the acceleration of the car. v2 – u2 = 0, Question 8. How does the difference in heights vary with time? Four cars A, B, C and D are moving on a levelled road. I am making more and more notes everyday. Answer: So, acceleration = \(\frac{6 \mathrm{m} / \mathrm{s}}{4 \mathrm{s}}\) = 1.5 m/s Write their names. Answer: NCERT Solutions for Class 6, 7, 8, 9, 10, 11 and 12, Extra Questions for Class 9 Science Chapter 8 Motion. (a) What type of motion is represented by OA? Question 7. Question 13. This chapter is very important chapters for your chemistry notes for class 9. Their distance versus time graphs are shown in figure. A cheetah is the fastest land animal and can achieve a peak velocity of 100 km/h up to distances less than 500 m. If a cheetah spots its prey at a distance of 100 m, what is the minimum time it will take to get its prey, if the average velocity attained by it is 90 km/h? Answer: Acceleration of an object is said to be uniform if it travels in a straight line and its velocity increases or decreases by equal amounts in equal intervals of time.For example, motion of a freely falling body. Answer: Question 4. (ii) The distance-time graph shows that the body is at rest between graph line B to C, it means no movement. Question 17. Answer: (ii) Reading the graph, velocity = 20 ms-1 (constant) Distance travelled by another body in 2 s = h2 = 0 + \(\frac{1}{2}\) g(2)2 = 2g So, the motion of object Q is non-uniform. Answer: (ii) Which of the bodies covers Initial velocity, u = 0.5 m/s [NCERT Exemplar] Answer: For train A, the initial velocity, Answer: If the motion is uniform, what will be the velocity after 10 s? Answer: Question 2. The negative sign implies decceleration. Hence, total distance, s = s1 + s2 Answer: As shown in the figure, the lines BC and BE are drawn from point B on the time and the velocity axes respectively, so that the initial velocity is represented by OA, the final velocity is represented by BC and the time interval t is represented by OC. Examine them carefully and state whether the motion of the objects is uniform or non-uniform. (v) Calculate the speed of the train between 10:40 AM to 11:00 AM. Question 10. Question 14. No. Question 2. Distance travelled in 5 seconds, s = u × 5 + \(\frac{1}{2}\)a × 5 2 (i) Which part of the graph shows the squirrel moving away from the tree? For a uniformly accelerated motion, velocity-time graph is always a straight line. Answer: Answer: They are relative terms. Question 2. [a = \(\frac{\Delta v}{\Delta t}\) = 0] Answer: So, the distance covered in last four seconds Answer: (a) OA is a straight line graph between speed and time, and it is sloping upward from O to A. = \(\frac{1}{2}\) × OP × OQ = \(\frac{1}{2}\) × 10 ms-1 × 10 s = 50 m Answer: The characteristics of distance-time graph for a non-uniform speed are: Question 7. If you are in search of the 9th class notes of physics all chapters which includes the 9th physics Solved numerical problems, short questions, long questions and MCQs all in pdf download available then you are at right page because here we have shared the Matric 9th Class Physics Notes pdf - MCQs, Questions … a = \(\frac{\mathrm{BD}}{t}\) or BD= at …..(2) s = ut Question 1. Distance is twice the distance between position P and Q. Question 11. Motion Class 9 Extra Questions Science Chapter 8 Extra Questions for Class 9 Science Chapter 8 Motion Motion Class 9 Extra Questions Very Short Answer Questions Question 1. An object is dropped from rest at a height of 150 m and simultaneously another object is dropped from rest at a height 100 m. What is the difference in their heights after 2 s if both the objects drop with same accelerations? Speed = Slope of distance-time graph. (iii) When is the train travelling at the highest speed? Also initial and final velocities are equal to \(\left(g \frac{T}{2}\right)\). Answer: Galileo Galilei and Isaac Newton. (a) maximum distance in 3rd second? Answer: What would be acceleration of a body if its velocity-time graph is a line parallel to the time axis? Question 5. So, AB represents uniform speed. (iii) We know, speed = slope of distance-time graph. (i) A to B Answer: What does the nature of the graph show ? (ii) average speed. (f) Find out the distance travelled by the body from A to B. Study the speed-time graph of a body given here and answer the following questions: (i) average velocity, or s = 5u + \(\frac{25}{2}\)a Question 6. Question 2. Speed = \(\frac{\text { Total distance }}{\text { Time }}=\frac{12}{11}\) = 1.09m/s. Thus, we can tell that motion is relative. v = 0; t = 10 s For example, when brakes are applied to a moving truck, its velocity gradually decreases. Time = 11 s. Distance travelled from A to B = 6 × 6 = 36m, Question 2. We can see that the object P covers a distance of 10 m in every fifteen minutes. I did not think that this would work, my best friend showed me this website, and it does! If the displacement of a body is zero, is it necessary that the distance coyered by it is also zero? A particle moves in a circle with O as centre and AO = OB = 5 cm, as radius, as shown in the figure. No. Suppose a ball is thrown vertically upwards from a position P above the ground. (i) The distance-time graph represents the line AB which shows the speed of the body. (iv) At what distance does the train slow down? Similarly, distance travelled in 4 seconds, s’ = 4u + \(\frac{1}{4}\)a Question 4. Here, DA = 6 m/s and DE = 10 – 4 = 6 s or BD = v – u …(1) = (s – s’) = (u + \(\frac{9}{2}\) a)m. Question 4. It also gives us information about the velocity of the body at any instant of time. (d) Find out the acceleration of the body. As the motion is uniform, the velocity remains 10 m/s after 10 s. Question 18. An electron moving with a velocity of 5 × 104 ms-1 enters into a uniform electric field and acquires a uniform acceleration of 104 ms-2 in the direction of its initial motion. Define one radian. The brakes applied to a car produce an acceleration of 6 ms-2 in the opposite direction to the motion.

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